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  4. Two point charges placed at a distance r in air experience a certain force. Then the distance at which they will experience the same force in a medium of dielectric constant K is

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Q. Two point charges placed at a distance $r$ in air experience a certain force. Then the distance at which they will experience the same force in a medium of dielectric constant $K$ is

Electric Charges and Fields

Solution:

$\frac{q_{1} q_{2}}{r^{2}}=\frac{q_{1} q_{2}}{K r^{' 2}}$ or $K r^{' 2}=r^{2} $ or $ r'=\frac{r}{\sqrt{K}}$