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  4. Two point charges of 1 μ C and -1 μ C are separated by a distance of 100 mathringA. A point P is at a distance of 10 cm from the midpoint and on the perpendicular bisector of the line joining the two charges. The electric field at P will be

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Q. Two point charges of $1 \,\mu C$ and $-1\, \mu C$ are separated by a distance of $100\,\mathring{A}$. A point $P$ is at a distance of $10 \,cm$ from the midpoint and on the perpendicular bisector of the line joining the two charges. The electric field at $P$ will be

Electric Charges and Fields

Solution:

The point lies on equatorial line of a short dipole.
$\therefore E=\frac{2ql}{4\pi\varepsilon_{0}r^{3}}$
$=\frac{9\times10^{9}\times10^{-6}\times10^{-8}}{\left(10^{-1}\right)^{3}}$
$=0.09\,N\,C^{-1}$