1. Tardigrade
  2. Question
  3. Chemistry
  4. Two platinum electrodes, each of area 10 sq. cm are fixed 1.5 cm apart in a conductivity cell. The cell contain 0.05 N solution of a salt with resistance 50 ohm. What is the equivalent conductivity of the salt solution?

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Two platinum electrodes, each of area$ 10 \,sq. \,cm$ are fixed $1.5 \,cm$ apart in a conductivity cell. The cell contain $0.05\, N$ solution of a salt with resistance $50 \,ohm$. What is the equivalent conductivity of the salt solution?

Electrochemistry

Solution:

$K =\frac{1}{R} \times \frac{l}{a}=\frac{1}{50} \times \frac{1.5}{10}$

Eq. conductance $=\kappa \times \frac{1000}{\text { Normality }}$

$=\frac{1}{50} \times \frac{1.5}{10} \times \frac{1000}{0.05}=60 \,S\, cm ^{2} eq ^{-1}$