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  4. Two plates are 2 cm apart, a potential difference of 10 V is applied between them, the electric field between the plates is

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Q. Two plates are $2 \,cm$ apart, a potential difference of $10\, V$ is applied between them, the electric field between the plates is

Chhattisgarh PMTChhattisgarh PMT 2005

Solution:

Electric field between the plates
$E=\frac{V}{d}=\frac{10}{2 \times 10^{-2}} $
$=500\, N / C$