Q. Two plane mirrors are inclined at $70^{\circ}$. A ray incident on one mirror at angle, $\theta$ after reflection falls on second mirror and is reflected from there parallel to first mirror. The value of $\theta$ is
Solution:
Different angles as shown in the figure.
$\theta+40^{\circ}=90^{\circ} $
$\therefore \theta=90^{\circ}-40^{\circ}=50^{\circ}$
