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Q. Two perfect gases at absolute temperatures $T_1$ and $ T_2$ are mixed. There is no loss of energy. The temperature of mixture of masses of molecules are $ m_1$ and $ m_2$ and the number of molecules in the gases are $n_1 $ and $ n_2 $ respectively, is

MHT CETMHT CET 2005Kinetic Theory

Solution:

We know E = $ \frac{3}{ 2} n kT $
k =Boltzmann's constant
$\therefore \frac{3}{ 2} n_1 k T_1 + \frac{3}{ 2} n_2 k T_2 = \frac{3}{ 2} (n_1 + n_2) k T $
T = $ \frac{ n_1 T_1 + n_2T_2 }{ n_1 + n_2 } $