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  4. Two pendulums have time-periods T and 5T/4. They start S.H.M. at the same time from the mean position. What will be the phase difference between them after the bigger pendulum has completed one oscillation? (in degree)

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Q. Two pendulums have time-periods $T$ and $5T/4$. They start S.H.M. at the same time from the mean position. What will be the phase difference between them after the bigger pendulum has completed one oscillation? (in degree)

Oscillations

Solution:

When bigger pendulum completes one oscillation, smaller Pendulum completes $\frac{5}{4}$ oscillation, i.e. difference of $\frac{1}{4}$ oscillation. Hence $\phi=90^{\circ}$.