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  4. Two parallel plates separated by a distance of 5 mm are kept at a potential difference of 50 V. A particle of mass 10-15 kg and charge 10-11 C enters in it with a velocity 107 m / s. The acceleration of the particle will be

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Q. Two parallel plates separated by a distance of $5\, mm$ are kept at a potential difference of $50\, V$. A particle of mass $10^{-15} kg$ and charge $10^{-11} C$ enters in it with a velocity $10^{7}\, m / s$. The acceleration of the particle will be

Electrostatic Potential and Capacitance

Solution:

$a=\frac{q E}{m}=\frac{q}{m}\left(\frac{V}{d}\right)$
$=\frac{10^{-11}}{10^{-15}} \times \frac{50}{5 \times 10^{-3}}$
$=10^{8} m / \sec ^{2}$