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  4. Two parallel plates have equal and opposite charge. When the space between them is evacuated, the electric field between the plates is 2 × 105 Vm - 1. When the space is filled with dielectric thel electric field becomes 1 × 105 Vm -1 . The dielectric constant of dielectric material is

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Q. Two parallel plates have equal and opposite charge. When the space between them is evacuated, the electric field between the plates is $ 2 \times 10^5 \, Vm^{ - 1}$. When the space is filled with dielectric thel electric field becomes $1 \times 10^5 Vm^{ -1}$ . The dielectric constant of dielectric material is

Punjab PMETPunjab PMET 2007Electric Charges and Fields

Solution:

K = $ \frac{ E_{ without \, dielectric }}{ E_{ with \, dielectric}} = \frac{ 2 \times 10^5 }{ 1 \times 10^5 } $ = 2