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Q. Two parallel plate capacitors have their plate areas $100\, cm ^{2}$ and $500\, cm ^{2}$ respectively. If they have the same charge and potential and the distance between the plates of the first capacitor is $0.5\, mm$, then the distance between the plates of the second capacitor is

Electrostatic Potential and Capacitance

Solution:

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$\frac{100 \varepsilon_{0}}{0.5}=\frac{500 \varepsilon_{0}}{d}$
$d=2.5 \,cm =0.25\, cm$