1. Tardigrade
  2. Question
  3. Physics
  4. Two parallel metal plates having charges + Q and -Q face each other at a certain distance between them. If the plates are now dipped in kerosene oil tank, the electric field between the plates will

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Two parallel metal plates having charges $+ Q$ and $-Q$ face each other at a certain distance between them. If the plates are now dipped in kerosene oil tank, the electric field between the plates will

JIPMERJIPMER 2013Electric Charges and Fields

Solution:

The electric field between two charged parallel plates placed in air is
$E = \frac{\sigma}{\varepsilon_0} = \frac{Q}{\varepsilon_0 A}$ ...(i)
When the parallel plates are immersed in kerosene oil tank of dielectric constant $K$, the electric field between the plates is
$E' =\frac{\sigma}{K \varepsilon_0 } = \frac{Q}{K \varepsilon_0 A} = \frac{E}{K}$ (Using (i))
$\therefore \, \frac{E'}{E} =\frac{1}{K}$
As $K > 1 $, so $E' < E$