Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Two objects $A$ and $B$ are placed at $15\, cm$ and $25\, cm$ from the pole in front of a concave mirros having radius of curvature $40\, cm$. The distance between images formed by the mirror is

JEE MainJEE Main 2023Ray Optics and Optical Instruments

Solution:

image
by mirror formula
$ \frac{1}{ v }+\frac{1}{ u }=\frac{1}{ f } $
$ \frac{1}{ v _1}+\frac{1}{-15}=\frac{1}{(-20)}$
$\frac{1}{ v _1}=-\frac{1}{20}+\frac{1}{15} $
$ =\frac{-3+4}{60}$
$ v _1=60\, cm $
$\frac{1}{ v _2}+\frac{1}{(-25)}=\frac{1}{(-20)}$
$\frac{1}{ v _2}=\frac{-1}{20}+\frac{1}{25} $
$ =\frac{-5+4}{100}=\frac{-1}{100} $
$ v _2=-100 \,cm $
$ d =60+100=160 \,cm$