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Q. Two nuclei have mass numbers in the ratio $8:125$ . The ratio of their nuclear radii is:

NTA AbhyasNTA Abhyas 2020Nuclei

Solution:

Here ,
$R = R_{0} A^{1 / 3}$
Since, $R = R_{0} A^{1 / 3}$
$\therefore \frac{R_{1}}{R_{2}}=\frac{A_{1}^{1/3}}{A_{2}^{1/3}}=\left(\right. \frac{A_{1}}{A_{2}} \left.\right)^{1/3} \\ \, =\left(\right. \frac{8}{125} \left.\right)^{1/3} \\ \, =\frac{2}{5}$
$\therefore $ The ratio of their radii = $2:5$