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Q.
Two moles of monoatomic gas is mixed with three moles of a diatomic gas. The molar specific heat of the mixture at constant volume is
Kinetic Theory
Solution:
Molar specific heat of the mixture at constant volume is
$\left(C_{V}\right)_{mixture} = \frac{n_{1}C_{V_1}+n_{2}C_{V_1}}{\left(n_{1}+n_{2}\right)}$
$= \frac{2\left(\frac{3}{2}R\right)+3\left(\frac{5}{2}R\right)}{2+3} = 2.1R$