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Q. Two moles of $HI$ were heated in a sealed tube at $440^{\circ} C$ till the equilibrium was reached. HI was found to be $22 \%$ decomposed. The equilibrium constant for dissociation is

Equilibrium

Solution:

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$K=\frac{\left[ H _{2}\right]\left[ I _{2}\right]}{[ HI ]^{2}}=\frac{0.22 \times 0.22}{(1.56)^{2}}=0.0199$