1. Tardigrade
  2. Question
  3. Chemistry
  4. Two moles of each reactant A and B are taken in a reaction flask. They react in the following manner, A(g)+B(g) leftharpoons C(g)+D(g) At equilibrium, it was found that the concentration of C is triple to that of B. The equilibrium constant for the reaction is

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Q. Two moles of each reactant $A$ and $B$ are taken in a reaction flask. They react in the following manner,
$A(g)+B(g) \rightleftharpoons C(g)+D(g)$
At equilibrium, it was found that the concentration of $C$ is triple to that of $B$. The equilibrium constant for the reaction is

AIIMSAIIMS 2009

Solution:

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$K_{p}=\frac{p_{C} \cdot p_{D}}{p_{A} \cdot p_{B}}$
$=\frac{\left(\frac{3 x}{V}\right)^{2}}{\left(\frac{2-3 x}{V}\right)^{2}}$
$=\frac{9 \times\left(\frac{1}{2}\right)^{2}}{4-12 \times \frac{1}{2}+9 \times\left(\frac{1}{2}\right)^{2}}$
$=9$