1. Tardigrade
  2. Question
  3. Chemistry
  4. Two metals X and Y form covalent halides. Both halides can act as Lewis acids and a catalyst in Friedel Crafts reaction. Halide of X is polymer in the solid state and a dimer in the vapour state which decomposes to monomer at 1200 K. However, halide of Y is a dimer in vapour state and becomes ionic in polar solvent. X and Y are respectively.

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Q. Two metals $X$ and $Y$ form covalent halides. Both halides can act as Lewis acids and a catalyst in Friedel Crafts reaction. Halide of $X$ is polymer in the solid state and a dimer in the vapour state which decomposes to monomer at $1200 K$. However, halide of $Y$ is a dimer in vapour state and becomes ionic in polar solvent. $X$ and $Y$ are respectively.

The s-Block Elements

Solution:

Covalent halides are formed by $Be$ and $Al$ among the metals given. The halide of $Al,$ ie, $Al _{2} Cl _{6}$ becomes ionic in polar solvent. Hence $Y$ is $A l .$ Halide of $B e$ is a polymer in solid state. Thus $X$ is $Be$.