Two masses, $m_{1}$ and $m_{2}$ are hanging from a support as shown in figure.
The tension in string $B C$
$T_{1}=($ total mass hanging on string $) g=m_{2} g$
Similarly, the tension in string $O A$
$T_{2}=($ total mass hanging on string $O A) g$
$T_{2}=\left(m_{1}+m_{2}\right) g$
Hence, the tension in the upper, string is
$T=\left(m_{1}+m_{2}\right) g$