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Q. Two long parallel wires are $30 \, cm$ apart carrying currents $10 \, A$ and $15 \, A$ respectively in the same direction. The force acting over a length of $5 \, m$ of the wires is

NTA AbhyasNTA Abhyas 2020Moving Charges and Magnetism

Solution:

Solution
Force acting between two parallel wire
$F=\frac{\mu _{0} i_{1} i_{2}}{2 \pi r}l$
$F=\frac{\left(2 \times 1 0^{- 7}\right) \left(10\right) \left(15\right)}{0.3}\times 5$
$F=5\times 10^{- 4} \, N$