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Q. Two long conductors, separated by a distance d carry current $I_1$ and $I_2$ in the same direction. They exert a force $F$ on each other. Now the current in one of them increased to two times and its direction reversed. The distance is also increased to $3d$. The new value of the force between them is

AIEEEAIEEE 2004Moving Charges and Magnetism

Solution:

Force between two long conductor carrying current
$F = \frac{\mu_{0}}{2\pi} \frac{I_{1}I_{2}}{d}\ell$
According to question
$F' = \frac{\mu _{0}}{2\pi } \frac{\left(-2I_{1}\right)I_{2}}{d}\ell$
From equation $\left(i\right)$ and $\left(ii\right)$, $F' = -\frac{3}{2}F.$