1. Tardigrade
  2. Question
  3. Chemistry
  4. Two liquids A and B have, PA0 and PB 0=1:3 at a certain temperature. Assume A and B form an ideal solution, and the ratio of mole of A to B in the liquid phase are 1:3, then mole fraction of A in vapour phase in equilibrium with the solution is yA . Calculate 10yA ?

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Q. Two liquids $A$ and $B$ have, $P_{A}^{0}$ and $P_{B}\_{}^{0}=1:3$ at a certain temperature. Assume $A$ and $B$ form an ideal solution, and the ratio of mole of $A$ to $B$ in the liquid phase are $1:3,$ then mole fraction of $A$ in vapour phase in equilibrium with the solution is $y_{A}$ . Calculate $10y_{A}$ ?

NTA AbhyasNTA Abhyas 2022

Solution:

$Pt=P_{A}^{0}x_{A}+P_{B}^{0}x_{B}=\frac{1}{4}P_{A}^{0}+\frac{3}{4}\times 3P_{A}^{0}$
$=\frac{10}{4}P_{A}^{0}=\frac{5}{2}P_{A}^{0}$
$P_{T}.Y_{A}=P_{A}^{0}x_{A}$
$\Rightarrow y_{A}=\frac{P_{A}^{0} x \frac{1}{4}}{\frac{5}{2} P_{A}^{0}}=\frac{1}{10}10y_{A}=10\times 0.1=1$