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  4. Two large parallel metal plates carry charges +Q and -Q respectively. A test charge q0 placed between them experiences a force F . If the separation between the plates is doubled, then the force on the test charge will be

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Q. Two large parallel metal plates carry charges $+Q$ and $-Q$ respectively. A test charge $q_{0}$ placed between them experiences a force $F$ . If the separation between the plates is doubled, then the force on the test charge will be

NTA AbhyasNTA Abhyas 2020Electrostatic Potential and Capacitance

Solution:

Initially, the force on charge $q_{0}$ is
Solution
$F = q_{0} E$
The electric field is,
$E = \frac{Q}{\epsilon _{0} A}$
If the separation between the plates is doubled $E$ will remain same as its independent of distance.
$\therefore F=same$