Q.
Two infinite long current carrying wires A and B are placed as shown in figure. Each wire carries same current $ I $ . The resultant magnetic field intensity at point P is
JamiaJamia 2011
Solution:
$ {{B}_{A}}={{B}_{B}}=\frac{{{\mu }_{0}}I}{2\pi \times \sqrt{2}a} $
So, $ B=\sqrt{B_{A}^{2}+B_{B}^{2}}=\frac{{{\mu }_{0}}I}{2\pi a} $
