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  4. Two identical parallel plate capacitors are connected in series and then joined in series with a battery of 100 V. A slab of dielectric constant K=3 is inserted between the plates of the first capacitor. Then, the potential difference across the capacitors will be, respectively,

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Q. Two identical parallel plate capacitors are connected in series and then joined in series with a battery of $100 \,V$. A slab of dielectric constant $K=3$ is inserted between the plates of the first capacitor. Then, the potential difference across the capacitors will be, respectively,

Electrostatic Potential and Capacitance

Solution:

$V_{1}=\frac{C \times 100}{3 C+C}=25\, V$ ,
$ V_{2}=100-25=75 \,V$