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  4. Two identical non-conducting solid spheres of same mass and charge are suspended in air from a common point by two non-conducting, massless strings of same length. At equilibrium, the angle between the strings is α. The spheres are now immersed in a dielectric liquid of density 800 kg m -3 and dielectric constant 21 . If the angle between the strings remains the same after the immersion, then

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Q. Two identical non-conducting solid spheres of same mass and charge are suspended in air from a common point by two non-conducting, massless strings of same length. At equilibrium, the angle between the strings is $\alpha$. The spheres are now immersed in a dielectric liquid of density $800\, kg \,m ^{-3}$ and dielectric constant $21$ . If the angle between the strings remains the same after the immersion, then

JEE AdvancedJEE Advanced 2020

Solution:

$\tan \alpha=\frac{F}{m g}=\frac{F / K}{m g-\rho_{t} v g} $
$\Rightarrow \rho_{0}=840\, kg / m ^{3} $
$T_{1} \cos \alpha=m g, T_{2} \cos \alpha=m g-\rho_{t} v g$
So, $T _{2}$ will decrease
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