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Q. Two identical cells connected in series send $10\,A$ current through a $5\Omega$ resistor. When they are connected in parallel, they send $8\,A$ current through the same resistance, the internal resistance of each cell is

Current Electricity

Solution:

For series combination $2 \xi = (5 + 2r) 10$ . For parallel combination $\xi = ( 5 + \frac{r}{2} )8$