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  4. Two identical capacitors C1 and C2 of equal capacitance are connected as shown in the circuit terminals a and b of the key k are connected to charge capacitor C1 using battery of emf V volt. Now disconnecting a and b the terminals b and c are connected. Due to this, what will be the percentage loss of energy ?

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Q. Two identical capacitors C$_1$ and C$_2$ of equal capacitance are connected as shown in the circuit terminals a and b of the key k are connected to charge capacitor C$_1$ using battery of emf V volt. Now disconnecting a and b the terminals b and c are connected. Due to this, what will be the percentage loss of energy ?Physics Question Image

NEETNEET 2019Electrostatic Potential and Capacitance

Solution:

$U_{\text{initial}} = \frac{1}{2}CV^2$
Loss $ = \frac{C.C}{2(C + C)}(V - 0)^2$
$ = \frac{1}{4} CV^2$
$\%$ Loss $ = \frac{\frac{1}{4} CV^2}{\frac{1}{2}CV^2} \times 100 = 50\%$