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Q. Two identical capacitors are first connected in series and then in parallel. The ratio of equivalent capacitance is

J & K CETJ & K CET 2013Electrostatic Potential and Capacitance

Solution:

Capacitor in series $\frac{1}{C_{s}}=\frac{1}{C}+\frac{1}{C}=\frac{2}{C}$
$\Rightarrow C_{s}=\frac{C}{2}$ Capacitor in parallel
$C_{p}=C+C=2 C$
$\therefore \frac{C_{g}}{C_{p}}=\frac{C}{2 \times 2 C}$
$=\frac{1}{4}$