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  4. Two identical balls A and B are released from the positions shown in the figure. They collide elastically on horizontal portion MN. The ratio of the respective heights attained by A and B after collision will be (neglect friction)

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Q. Two identical balls A and B are released from the positions shown in the figure. They collide elastically on horizontal portion MN. The ratio of the respective heights attained by A and B after collision will be (neglect friction)Physics Question Image

Solution:

Since collision is elastic hence velocities will be exchanged.
After collision $v_A=\sqrt{2gh}$
$v_B=\sqrt{8gh}$
$H_A=\frac{v^2_A}{2g}=h$
$H_B = \frac {v^2_B}{2g} = 4h$
$\frac{H_A}{H_B}=\frac{1}{4}$