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  4. Two hollow conducting spheres of radii R1 and R2 (R1 > >R2) have equal charges. The potential would be:

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Q. Two hollow conducting spheres of radii $R_{1}$ and $R_{2}$ $\left(R_{1} > >R_{2}\right)$ have equal charges. The potential would be:

NEETNEET 2022Electrostatic Potential and Capacitance

Solution:

$V =\frac{1}{4 \pi \epsilon_{0}} \cdot \frac{ Q }{ R } $
$\frac{1}{4 \pi \epsilon_{0}}=$ constant
$ Q =$ same (Given)
$\therefore V \propto \frac{1}{ R }$
$\therefore$ Potential is more on smaller sphere.