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Q. Two Grand Masters Anand and Karpov, play 3 games of chess. The probability that Anand wins a game is 0.5, looses with probability 0.3 and ties with probability 0.2. If he plays 3 games then the chance that he wins atleast two games, is

Probability - Part 2

Solution:

P (T or L) = 0.5 = P (E) say
P (W W E or W E W or E W W or W W W)
$=4 \cdot \frac{5}{10} \cdot \frac{5}{10} \cdot \frac{5}{10}=\frac{1}{2}$