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  4. Two forces of magnitudes 8 N and 15 N respectively act at a point so as to make the resultant force of 17 N. The angle between the forces has to be

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Q. Two forces of magnitudes 8 N and 15 N respectively act at a point so as to make the resultant force of 17 N. The angle between the forces has to be

AMUAMU 1996

Solution:

: Resultant force $ =17\text{ }N $ $ \therefore $ $ {{R}^{2}}-{{P}^{2}}+{{Q}^{2}}+2PQcos\theta $ or $ {{(17)}^{2}}={{(8)}^{2}}+{{(15)}^{2}}+2.PQcos\theta $ or $ 289=64+225+2PQcos\theta $ or $ \cos \theta =0 $ or $ \theta =90{}^\circ $