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Q.
Two equal resistance when connected in series to a battery, consume electric power of $60\, W$. If these resistances are now connected in parallel combination to the same battery, the electric power consumed will be :
In series condition, equivalent resistance is 2R
thus power consumed is 60W $ = \frac{ \varepsilon^2}{2R}$
In parallel condition, equivalent resistance is R/2 thus new power is
$P' = \frac{\varepsilon^2}{(R / 2)} $
or $P' = 4\, P = 240\, W$