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  4. Two equal heavy sphers, each of radius r, are in equilibrium within a smooth cup of radius 3 r. The ratio of reaction between the cup and one sphere and that between the two sphere is

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Q. Two equal heavy sphers, each of radius $r$, are in equilibrium within a smooth cup of radius $3 r$. The ratio of reaction between the cup and one sphere and that between the two sphere isPhysics Question Image

BITSATBITSAT 2017

Solution:

$\sin \theta=\frac{1}{2}$
Thus, $ N_{1} \sin \theta=N_{2}$
$\therefore \frac{N_{1}}{N_{2}}=\frac{1}{\sin \theta}=2$.

Solution Image