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  4. Two elements X (at. mass 16) and Y (at.mass14) combine to form compounds A, B and C. The ratio of different masses of Y which combine with a fixed mass of X in A, B and C is 1: 3: 5. If 32 parts by mass of X combines with 84 parts by mass of Y in B, then in C, 16 parts by mass of X will combine with :

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Q. Two elements X (at. mass 16) and Y (at.mass14) combine to form compounds A, B and C. The ratio of different masses of Y which combine with a fixed mass of X in A, B and C is 1 : 3 : 5. If 32 parts by mass of X combines with 84 parts by mass of Y in B, then in C, 16 parts by mass of X will combine with :

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Solution:

In $B$, $32$ parts of $X$ combines with $Y=84$ parts
$\therefore $ $16$ parts of $X$ will combine with $Y=42$ parts
Now number of parts of $X$ in both $B$ and $C$ is equal
Different masses of $Y$ which combine with a fixed mass of $X$ in $B$ and $C$ are in the ratio $3 : 5$
$\therefore $ $\frac{\text{Mass of Y in B}}{\text{Mass of Y in C}}=\frac{3}{5}$
$\frac{\text{42 parts}}{\text{Mass of Y in C}}=\frac{3}{5}$
$\therefore $ Mass of Y in C $=\frac{5}{3}\times42$
$=70$ parts