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Q.
Two electric bulbs rated $P_{1}$ watt $V$ volts and $P_{2}$ watt $V$ volts are connected in parallel and $V$ volts are applied to it. The total power will be
Current Electricity
Solution:
If resistances of bulbs are $R_{1}$ and $R_{2}$,
respectively, then in parallel $\frac{1}{R_{P}}=\frac{1}{R_{1}}+\frac{1}{R_{2}}$
$\Rightarrow \frac{1}{\left(\frac{V^{2}}{P_{p}}\right)}=\frac{1 \cdot}{\left(\frac{V^{2}}{P_{1}}\right)}+\frac{1}{\left(\frac{V^{2}}{P_{2}}\right)} $
$\Rightarrow P_{P}=P_{1}+P_{2}$