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Q.
Two electric bulbs $A$ and $B$ are rated $60$ and $100\, W$, respectively. If they are connected in parallel to the same source, then
Current Electricity
Solution:
Given $P_{A}=60 \,W , P_{B}=100\, W$. We know that current flowing through the bulb is $I=P / V$. We also know that as both the bulbs are connected in parallel, potential difference $(V)$ across both the bulbs is the same. Thus, $I \propto P$. Since the power of bulb $B$ is greater than that of bulb $A$, bulb $B$ draws more current than bulb $A$.