Given two dice are thrown simultaneously.
$\because$ Total number of outcomes $=36$
Also, sum of numbers is $5$,
i.e. $\{(1,4),(2,3),(3,2)$, $(4,1)\}$
$\therefore $ Favourable outcomes $=4$
$\therefore $ Required probability $=\frac{4}{36}=\frac{1}{9}$