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  4. Two cylindrical rods of uniform cross-sectional area A and 2 A, having free electrons per unit volume 2 n and n respectively are joined in series. A current I flows through them in steady state. Then the ratio of drift velocity of free electrons vL in left rod to drift velocity of electrons in the right operatornamerod vR is

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Q. Two cylindrical rods of uniform cross-sectional area $A$ and $2 A$, having free electrons per unit volume $2 n$ and $n$ respectively are joined in series. A current $I$ flows through them in steady state. Then the ratio of drift velocity of free electrons $v_{L}$ in left rod to drift velocity of electrons in the right $\operatorname{rod} v_{R}$ isPhysics Question Image

Current Electricity

Solution:

Since current $I=n e A v d$ through both rods is same,
$\therefore 2(n) e A v_{L}=n e(2 A) v_{R}$ or $\frac{v_{L}}{v_{R}}=1$