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Q. Two coherent sources produce waves of different intensities which interfere. After interference, the ratio of the maximum intensity to the minimum intensity is $16$. The intensity of the waves are in the ratio:

JEE MainJEE Main 2019Wave Optics

Solution:

$\frac{I_{\max}}{I_{\min}} = 16 $
$ \Rightarrow \frac{A_{\max }}{A_{\min }} = 4 $
$ \Rightarrow \frac{A_{1} + A_{2}}{A_{1} - A_{2}} = \frac{4}{1} $
Using componendo & dividendo.
$ \frac{A_{1} }{A_{2}} = \frac{5}{3} \Rightarrow \frac{I_{1}}{I_{2}} = \left(\frac{5}{3}\right)^{2} = \frac{25}{9} $