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Q. Two co-axial wires one solid and one hollow, each carry the same current I in opposite directions. The radius of the inner wire $r_1$The inner radius of the hollow wire is $r_2$. What is the magnetic induction at a point where $r_2 < r < r_1$

Solution:

Here $B \times 2 \, \pi \, r = \mu_0 \, I$ or $B = \frac{\mu_0 \, I}{2 \, \pi \, r}$