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Q. Two circuits have coefficient of mutual induction of $0.09$ henry. Average e.m.f. induced in the secondary by a change of current from 0 to $20$ amperes in $0.006$ second in the primary will be

Electromagnetic Induction

Solution:

$|e|=M \frac{d i}{d t}=0.09 \times \frac{20}{0.006}=300\, V$