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Q. Two charges $+q$ and $-q$ are kept apart. Then at any point on the right bisector of line joining the two charges

EAMCETEAMCET 2008

Solution:

At equitorial point
$E_{e}=\frac{1}{4 \pi \varepsilon_{0}} \frac{p}{r^{3}}$
(directed from $+q$ to $-q$ ) and $V_{e}=0$