Q.
Two charges $-Q$ and $-9Q$ are placed at a separation of $3m.$ Where should charge q be placed so that net force on it is zero ?

NTA AbhyasNTA Abhyas 2020
Solution:

Solution:
$k\frac{Q q}{x^{2}}=k\frac{q Q q}{\left(\right. 3 - x \left(\left.\right)^{2}}$