Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Two charges $Q_{1}=18 \,\mu C$ and $Q_{2}=-2\, \mu C$ are separated by a distance $R$, and $Q_{1}$ is on the left of $Q_{2}$. The distance of the point where the net electric field is zero is

Electric Charges and Fields

Solution:

$\frac{k Q_{2}}{x^{2}}=\frac{k Q_{1}}{(x+R)^{2}}$ or $x=\frac{R}{2}$

Solution Image