Q. Two charges $Q_{1}=18 \,\mu C$ and $Q_{2}=-2\, \mu C$ are separated by a distance $R$, and $Q_{1}$ is on the left of $Q_{2}$. The distance of the point where the net electric field is zero is
Electric Charges and Fields
Solution:
$\frac{k Q_{2}}{x^{2}}=\frac{k Q_{1}}{(x+R)^{2}}$ or $x=\frac{R}{2}$
