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  4. Two charges of 10 μ C are placed at the corners A and B of an equilateral triangle of side length 0.5 m in air. The electric potential at C is

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Q. Two charges of $10 \mu C$ are placed at the corners $A$ and $B$ of an equilateral triangle of side length $0.5 m$ in air. The electric potential at $C$ is

Electrostatic Potential and Capacitance

Solution:

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According to the principle of superposition
$V _{ net }= V _{ AC }+ V _{ BC }$
$V _{ net }=\frac{ Kq }{ r }+\frac{ Kq }{ r }$
$V _{ net }=\frac{2 Kq }{ r }$
$V_{\text {net }}=\frac{2 \times 9 \times 10^{9} \times 10 \times 10^{-6}}{0.5 m }$
$=36 \times 10^{4} V$