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  4. Two charges are at a distance d apart. If a copper plate of thickness (d/2) is kept between them, the effective force will be

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Q. Two charges are at a distance $d$ apart. If a copper plate of thickness $ \frac{d}{2} $ is kept between them, the effective force will be

ManipalManipal 2010Electric Charges and Fields

Solution:

From Coulomb's law, electric force between two charges is directly proportional to product of charges and inversely proportional to square of distance between them. That is
$F=k \frac{q_{1} q_{2}}{d^{2}}$
where, $k=\frac{1}{4 \pi \varepsilon_{0}}=$ proportionality constant. If a medium is placed between the charges, then
$F'=\frac{1}{4 \pi \varepsilon_{0} K} \frac{q_{1} q_{2}}{d^{2}}$
Since, medium placed between the charges is a metallic plate, so for it $K=\infty$
Hence, $F'=0$ (zero)