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Q. Two charges $ 4q $ and $ q $ are placed at a distance $ I $ another charge Q is placed at the midpoint of line joining the charges $ 4q $ and $ q $ If net force on charge $ q $ is zero, then value of $ Q $ is:

Rajasthan PMTRajasthan PMT 1995

Solution:

On charge Q, both 4q and q charge apply force.
Net force of Q should be zero. $ K\frac{4q.\,\,q}{{{l}^{2}}}+\frac{K\,\,Q.q}{{{(1/2)}^{2}}}=0 $ $ Q=-q $

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