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Q.
Two charges $+4 e$ and $+e$ are at a distance $x$ apart. At what distance a charge $q$ must be placed from charge $+e$ so that it is in equilibrium?
Electric Charges and Fields
Solution:
For equilibrium of $q$,
$\left|F_{1}\right|=\left|F_{2}\right|$
$\Rightarrow x_{2}=\frac{x}{\sqrt{\frac{Q_{1}}{Q_{2}}}+1}=\frac{x}{\sqrt{\frac{4 e}{e}}+1}=\frac{x}{3}$
