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  4. Two charges +3.2 × 10-19 and -3.2 × 10-19 C placed at 2.4 mathringA apart form an electric dipole. It is placed in a uniform electric field of intensity 4 × 105 V / m. The electric dipole moment is

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Q. Two charges $+3.2 \times 10^{-19}$ and $-3.2 \times 10^{-19} C$ placed at $2.4 \,\mathring{A}$ apart form an electric dipole. It is placed in a uniform electric field of intensity $4 \times 10^{5} V / m$. The electric dipole moment is

Electric Charges and Fields

Solution:

Dipole moment, $p=q(2 l)$
$=3.2 \times 10^{-19} \times\left(2.4 \times 10^{-10}\right)$
$=7.68 \times 10^{-29} C - m$